Q.

Let R1  be a relation defined in the set of real numbers by aR1b1+ab>0,  then R   is

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a

equivalence relation

b

symmetric

c

anti symmetric

d

transitive

answer is C.

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Detailed Solution

 aRb1+ab>0
i) (a,a)R;    since  1+a.a=1+a2>0
ii)   (a,b)R1(b,a)R
1+ab>01+ba>0  
So,R1 is reflexive and  symmetric
 

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