Q.

Let S={4,6,9} and T={9,10,11,.....,1000}. If A={a1+a2+......+ak:kN,a1,a2,a3,.....,akS}, then twice the sum of all the elements in the set TA is equal to___________.

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answer is 22.

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Detailed Solution

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Given S={4,6,9} and T={9,10,11,.....,1000}

Where,  A={a1+a2+......+ak:KN} & aiS

Here by the definition of set 'A'

A={a:a=4x+6y+9z}

Except the element 11, every element of set T is of the form 4x+6y+9z for some x,y,zW

   TA={11}

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