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Q.

Let S be the set of all-natural number, for which the line xa+yb=2 is tangent to the curve xan+ybn=2 at the point (a, b), ab≠0 then

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a

s=ϕ

b

n(s)=1

c

S={2k:kN}

d

S=N

answer is D.

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Detailed Solution

(xa)n+(yb)n=2
Slope of the tangent (a, b)
dydx]=ba
Equation of tangentyb=ba(xa)                                              xa+yb=2,nN                                             S=N

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