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Q.

Let S be the set of all the natural numbers, for which the line xa+yb=2 is a tangent to the curve xan+ybn=2 at the point (a,b),ab0. Then:

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a

n(S)=1

b

S=ϕ

c

S=N

d

S={2k:kN}

answer is D.

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Detailed Solution

xan+ybn=2  Slope of tangent at (a, b)  nxan11a+nxbn11bdydx=0dydx(a,b)=ba  Equation of tangent  is yb=ba(xa)xa+yb=2nN

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