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Let S₁ and S₂ be the two slits in Young’s double slit experiment. If central maxima is observed at ‘P’ and angle $S_{1} {PS}_{2} = θ$ , then the fringe width for the light of wavelength ' $λ$ ' will be (Assume $θ$ to be a small angle)

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$λ θ$

$\frac{λ}{θ}$

$\frac{λ}{2 θ}$

$\frac{2 λ}{θ}$

answer is A.

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Detailed Solution

$θ = \frac{d}{D}$

$β = \frac{λD}{d} = \frac{λ}{θ}$

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