Q.

Let six children B1,B2,B3,B4,B5,B6 each have a fair 6 sided die which they roll simultaneously. Let E denotes the event that atleast three of them roll a prime number and F denotes the event that  B1,B2,B3 throw a prime number. If the conditional probability of F given E is equal to ab where a and b are coprime then which is/are CORRECT ?

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a

2a+b=29

b

|ab|=10

c

ab84

d

b-4a=0

answer is A, C.

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Detailed Solution

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P(Prime number) =12
p=12;q=12;n=6P(E)=P(X3)= 6C3+6C4+6C5+6C664=4264=2132P(F)=121212=18P(F/E)=P(FE)P(E)=P(F)P(E)=183221=421=aba=4 and b=21

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