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Q.

Let the curve ‘C’ be mirror image of parabola y2 = 4x w.r.t to line  x + y + 4 = 0. It A & B are points of intersections of ‘C’ with y=-5  then diameter of the least circle passing through A & B

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answer is 4.

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Detailed Solution

Image of (t2, 2t) w.r.t to x + y + 4 = 0 is (-(2t + 4), - (t2 + 4))
Solving with y = - 5 we get t=±1

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