Let the point $\mathrm{P}(\mathrm{\alpha }, \mathrm{\beta })$ be at a unit distance from each of the two lines ${\mathrm{L}}_1:3\mathrm{x}-4\mathrm{y}+12=0$, and ${\mathrm{L}}_2:8\mathrm{x}+6\mathrm{y}+11=0$. If P lies below L₁ and above L₂, then $100(\mathrm{\alpha }+\mathrm{\beta })$ is equal to