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Q.

Let three vectors a¯,b¯,c¯ be such that a¯×b¯=c¯, b¯×c¯=a¯ and |a¯|=2 Then which of the following is NOT TRUE?

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a

|3a¯+b¯2c¯|2=51

b

a¯×((b¯+c¯)×(b¯c¯))=0¯

c

[a¯b¯c¯]+[c¯a¯b¯]=8

d

Projection of a¯ on b¯×c¯ is 2

answer is C.

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Detailed Solution

a¯×b¯=c¯ c¯  is perpendicular to a¯=b¯
b¯×c¯=a¯a¯  is perpendicular to  b¯=c¯
So a¯,b¯,c¯ are mutually perpendicular 
a¯×b¯=c¯|a||b|=|c¯||b¯|=|c¯|2 b¯×c¯=a¯|b¯||c¯|=|a¯||c|=2 |b¯|=1

 1) [a¯b¯c¯]+[c¯a¯b¯]=2[a¯b¯c¯]=2|a||b||c|=8

2) a¯ is parallel to b¯×c¯  
So Projection of a¯ on b¯×c¯=a¯(b¯×c¯)|b¯×c¯|=[abc]|b||c|=42=2
3) |3a¯+b¯2c¯|2=9|a|2+|b¯|2+4|c|2=53

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