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Q.

Let two points be A(1, -1) and B(0, 2) if a point P(a,b) be such that the area of $△$ PAB is 5 sq units and it lies on the line 3x+y-4 $λ$ =0 then $λ$ is

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a

$3 o r - 2$

b

$2 o r 5$

c

$2 o r 1$

d

$- 3 o r - 1$

answer is A.

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Detailed Solution

$A = (1, - 1); B (0, 2); p (a, b) A r e a o f t r i a n g l e P A B i s 5$
$\begin{array}{l} \Rightarrow |3 a + b - 2| = 10 \\ \Rightarrow 3 a + b - 12 = 0 (o r) 3 a + b + 8 = 0 \end{array}$
$P (a, b) l i e s o n 3 x + y - 4 λ = 0 \begin{array}{l} \Rightarrow 3 a + b - 4 λ = 0 \\ \Rightarrow λ = 3 o r - 2 \end{array}$

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