Let U=1,2,3,4,5,6,7,8,9,10, A=1,2,5, B=6,7, then A∩B' is

B'=1,2,3,4,5,8,9,10∴A∩B'=1,2,5∩1,2,3,4,5,8,9,10=1,2,5=A

Let U=1,2,3,4,5,6,7,8,9,10, A=1,2,5, B=6,7, then A∩B' is

B'=1,2,3,4,5,8,9,10∴A∩B'=1,2,5∩1,2,3,4,5,8,9,10=1,2,5=A

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Let $U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}, A = \{1, 2, 5\}, B = \{6, 7\},$ then $A \cap B^{'}$ is

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$B^{'}$

$A$

$A^{'}$

$B$

answer is B.

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Detailed Solution

$B^{'} = \{1, 2, 3, 4, 5, 8, 9, 10\}$

$∴ A \cap B^{'} = \{1, 2, 5\} \cap \{1, 2, 3, 4, 5, 8, 9, 10\} = \{1, 2, 5\} = A$

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Let U=1,2,3,4,5,6,7,8,9,10, A=1,2,5, B=6,7, then A∩B' is

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Let $U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}, A = \{1, 2, 5\}, B = \{6, 7\},$ then $A \cap B^{'}$ is