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Let us consider an endothermic reaction which is non-spontaneous at the freezing point of water. However, the reaction is spontaneous at the boiling point of water. Choose the correct option.

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Both $Δ$ H and $Δ$ S are (+ve)

$Δ$ H is (–ve) but $Δ$ S is (+ve)

$Δ$ H is (+ve) but $Δ$ S is (–ve)

Both $Δ$ H and $Δ$ S are (–ve)

answer is A.

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Detailed Solution

Reaction is spontaneous at relatively high temperature and non-spontaneous at low temperature $Δ$ G = $Δ$ H – T $Δ$ S
It is only possible when $Δ$ H and $Δ$ S both are positive.

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