Let us consider the molecules given below NF3 NCl3 NBr3PF3 PCl3 PBr3AsF3 AsCl3 AsBr3If a = no. of molecules having bond angle more than that of AsH3b = no. of molecules having bond angle more than AsF3 Find the value of a−b.

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Let us consider the molecules given below
$\begin{array}{l} N F_{3} N C l_{3} N B r_{3} \\ P F_{3} P C l_{3} P B r_{3} \\ A s F_{3} A s C l_{3} A s B r_{3} \end{array}$
If a = no. of molecules having bond angle more than that of $A s H_{3}$
b = no. of molecules having bond angle more than $A s F_{3}$
Find the value of $a - b .$

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$a = 9, b = 8$

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