Q.

Let x < 1, then value of x2+22x+112x+1x+21331 is

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a

non-negative

b

non-positive 

c

negative

d

positive

answer is C.

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Detailed Solution

Applying R1R1R2 and R2R2R3 reduce the determinant to

x22x+1x102x2x10331=(x1)32(x1)2                                          =(x1)2(x12)                                          =(x1)2(x3),

which is clearly negative for x < 1.

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