Let x = 2 be a root of the equation ${\mathrm{x}}^2+\mathrm{px}+\mathrm{q}=0$ and $\mathrm{f}\left(\mathrm{x}\right)=\left\{\begin{array}{cc}\frac{1-\cos \left({\mathrm{x}}^2-4\mathrm{px}+{\mathrm{q}}^2+8\mathrm{q}+16\right)}{(\mathrm{x}-2\mathrm{p}{)}^4}& ,\mathrm{x}\ne 2\mathrm{p}\\ 0& ,\mathrm{x}=2\mathrm{p}\end{array}\right.$
Then  $\underset{\mathrm{x}\to 2{\mathrm{p}}^{+}}{lim} \left[f\left(x\right)\right]$
Where [. ]  denotes greatest integer function, is