Let X represent the difference between the number of heads and the number of tails obtained when a coin is tossed 6 times. Then possible values of X is

A coin is tossed six times and X represents the difference between the number of heads and the number of tails 

$\begin{array}{rcl}\therefore \mathrm{X}(6\mathrm{H}, 0\mathrm{T})& =& |6-0|=6\\ \mathrm{X}(5\mathrm{H}, 1\mathrm{T})& =& |5-1|=4\\ \mathrm{X}(4\mathrm{H}, 2\mathrm{T})& =& |4-2|=2\\ \mathrm{X}(5\mathrm{H}, 3\mathrm{T})& =& |3-3|=0\\ \mathrm{X}(2\mathrm{H}, 4\mathrm{T})& =& |2-4|=2\\ \mathrm{X}(1\mathrm{H}, 5\mathrm{T})& =& |1-5|=4\\ \mathrm{X}(0\mathrm{H}, 6\mathrm{T})& =& |0-6|=6\end{array}$

$\therefore$ The Values of X are ={0, 2, 4, 6}