Let y be an implicit function of x defined by x2x−2xxcoty−1=0. Then absolute value of y1(1)equals

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Let $y$ be an implicit function of $x$ defined by $x^{2 x} - 2 x^{x} \cot y - 1 = 0$ . Then absolute value of $y^{1} (1)$ equals

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Detailed Solution

At $x = 1 \Rightarrow y = \frac{π}{2}$
Differentiate & substitute $x = 1 & y = \frac{π}{2}$

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