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Q.

Let y=(esinx1)4+(cosx1)3esinx+(exex)3+x3+2x2+4ex  
The value of y''(0) is  

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a

8

b

8

c

4

d

4

answer is D.

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Detailed Solution

At x = 0, y = 4
exy=x3+2x2+4y''(0)=8 
For y''(0),(esinx1)4+(cosx1)3esinx+(exex)3 is always gives zero at x = 0

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Let y=(esinx−1)4+(cosx−1)3esinx+(ex−e−x)3+x3+2x2+4ex  The value of y''(0) is