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Let Z be the set of all integers, $A = (x, y) ∈ Z × Z : (x − 2) 2 + y 2 ≤ 4$ $B = {(x, y) ∈ Z × Z : x 2 + y 2 ≤ 4} a n d$ $C = {(x, y) ∈ Z × Z : (x − 2) 2 + (y − 2) 2 ≤ 4)$

If the total number of relations from $A ∩ B t o A ∩ C$ is $2 p$ , then the value of p is

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answer is B.

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Detailed Solution

Number of relations from set A to set B is

2 n (A) × n (B)

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