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Q.

Let z satisfies  z3=α3z13+(1α)3z23+3(αα2)zz1z2 and f:R[0,),f(α)=|z|2, find minimum value of f(α) given that z1=3+4i  and  z2=12i

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answer is 3.

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Detailed Solution

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 z3+(αz1)3+((1α)z2)3=3z(αz1)((1α)z2)

zαz1(1α)z2=0,αR

So, |z| is perpendicular distance from  (0,0) to line joining the points (3,4)  and (1,2)

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