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Q.

Let z0 be a root of the quadratic equation, x2+x+1=0. If z=3+6iz081−3iz093 then arg z =

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a

π3

b

π4

c

π6

d

0

answer is A.

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Detailed Solution

z0=ω  or  ω2   (where ω is a non-real cube root of unity).

z=3+6i(ω)81−3i(ω)93=3+3i⇒arg  z =π4

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