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Q.

Let z1, z2 and z3 be three complex numbers on the circle |z|=1 with argz1=π4,argz2=0 and argz3=π4.If z1z¯2+z2z¯3+z3z¯12=α+β2,α,βZ, then the value of α2+β2 is :

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a

41

b

29

c

24

d

31

answer is D.

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Detailed Solution

Z1=eiπ4,Z2=1,Z3=eiπ4

z1z¯2+z2z¯3+z3z¯12=eiπ4×1+1×eiπ4+eiπ4×eiπ42

=eiπ4+eiπ4+eiπ42

=2eiπ4+i2==|22i+i|2

=(2)2+(12)2=2+1+222=522

α=5,β=2

α2+β2=29

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Let z1, z2 and z3 be three complex numbers on the circle |z|=1 with arg⁡z1=−π4,arg⁡z2=0 and arg⁡z3=π4.If z1z¯2+z2z¯3+z3z¯12=α+β2,α,β∈Z, then the value of α2+β2 is :