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Q.

Let  zk=cos(2kπ10)+isin(2kπ10);k=1,2,......,9

List-I

List-II

(P)For each zk there exists a zj such that zk.zj=1(1)True
(Q)There exist a k{1,2,.....9} such that z1.z=zk has no solution z in the set of complex numbers(2)False
(R)|1z1||1z2|........|1z9|10 equals(3)1
(S)1k=19cos(2kπ10)equals(4)2
  (5)Cannot be decided

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a

P1;  Q2;  R3;  S4

b

P2;   Q5;  R3;  S4

c

P1;  Q2;  R4;  S3

d

P5;  Q5;  R1;  S4

answer is C.

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