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Q.

Let θ0,π4  and t1=tanθtanθt2=tanθcotθt3=cotθtanθ and t4=cotθcotθ then  

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a

t4>t3>t1>t2

b

t3>t1>t2>t4

c

t1>t2>t3>t4

d

t2>t3>t1>t4

answer is B.

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Detailed Solution

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 In 0,π4,tanθ<1 and cotθ>1(cotθ)cotθ>(cotθ)tanθ>(tanθ)tanθ>(tanθ)cotθ⇒∴t4>t3>t1>t2

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