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Q.

Let $γ_{1}$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $γ_{2}$ be the similar ratio of diatomic gas . Considering the diatomic gas molecule as a rigid , the ratio , $\frac{γ_{1}}{γ_{2}}$ is :

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a

$\frac{25}{21}$

b

$\frac{21}{25}$

c

$\frac{27}{35}$

d

$\frac{35}{27}$

answer is B.

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Detailed Solution

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For Mono atomic gas, $γ_{1}$ =5/3.

For Diatomic gas, $γ_{2}$ =7/5.

So, $\frac{γ_{1}}{γ_{2}} = \frac{5 / 3}{7 / 5} = \frac{25}{21}$

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Let γ1be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ2 be the similar ratio of diatomic gas . Considering the diatomic gas molecule as a rigid , the ratio , γ1γ2 is :