Let −2−13i3=x+iy27(i=−1), where x and y are real numbers, then y−x equals

Given -2-13i3=x+iy27−(6+i)327=x+iy27⇒−(198+107i)=x+iyx=−198 and y=−107∴y−x=198−107=91

Let −2−13i3=x+iy27(i=−1), where x and y are real numbers, then y−x equals

Given -2-13i3=x+iy27−(6+i)327=x+iy27⇒−(198+107i)=x+iyx=−198 and y=−107∴y−x=198−107=91

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Let ${(- 2 - \frac{1}{3} i)}^{3} = \frac{x + i y}{27} (i = \sqrt{- 1})$ , where x and y are real numbers, then $y - x$ equals

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Given ${(- 2 - \frac{1}{3} i)}^{3} = \frac{x + i y}{27}$

$\frac{- (6 + i)^{3}}{27} = \frac{x + i y}{27} \Rightarrow - (198 + 107 i) = x + i y$

$x = - 198$ and $y = - 107 ∴ y - x = 198 - 107 = 91$

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Let −2−13i3=x+iy27(i=−1), where x and y are real numbers, then y−x equals

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Let ${(- 2 - \frac{1}{3} i)}^{3} = \frac{x + i y}{27} (i = \sqrt{- 1})$ , where x and y are real numbers, then $y - x$ equals