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Let $3 x - 2 y + 5 = 0$ be a line, then points $(- 3, 4) (2, - 1)$ lies

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same side of the line

origin side of the line

opposite side of the line

none

answer is B.

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Detailed Solution

$\begin{array}{l} L = 3 x - 2 y + 5 = 0 \\ L_{11} = L_{(- 3, 4)} = 3 (- 3) - 2 (4) + 5 = - 9 - 8 + 5 = - 12 \\ L_{22} = L_{(2, - 1)} = 3 (2) - 2 (- 1) + 5 = 6 + 2 + 5 = 13 \\ L_{11} > 0 a n d L_{22} < 0 a n d C = 5 > 0 \end{array}$

So, both points lies origin side of line.

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