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Q.

Let A=1,2,3,5,8,9. Then the number of possible functions f : A  A such that f(m. n) = f(m). f(n) for every m ,n  A with m.nA is equal to______.

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answer is 432.

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Detailed Solution

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f(1) = f(1 x 1) = f(1) x f(1) f(1) = 1
f(9) = f(3x 3) = f(3) x f(3) f(3) = 1, f(9) = 1 or f(3) = 3, f(9) = 9
If f(1) = 1, f(3) = 1, f(9) = 1
Then f(2), f(5), f(8) each mapped in 6 ways  
no.of ways = 63 = 216
 no.of ways = 216, Total ways = 216 + 216 = 432

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Let A=1,2,3,5,8,9. Then the number of possible functions f : A → A such that f(m. n) = f(m). f(n) for every m ,n ∈ A with m.n∈A is equal to______.