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Q.

Let a1=8, a2, a3 ....., an be an A.P. If the sum of its first four terms is 50 and the sum of its last four terms is 170, then the product of its middle two terms is_______. 

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answer is 754.

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Detailed Solution

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4a + 6d = 50d = 3
4a + (4n - 10) ·3 = 170 n = 14
a7 = 26, a8 = 29
a7a8 = 754

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