Let $\mathrm{A}(\mathrm{\alpha },-2),\mathrm{B}(\mathrm{\alpha },6)\text{ and }\mathrm{C}\left(\frac{\mathrm{\alpha }}{4},-2\right)$ be vertices of a $\mathrm{△}\mathrm{ABC}$. If $\left(5,\frac{\mathrm{\alpha }}{4}\right)$ is isthe circumcentre of $\mathrm{△}\mathrm{ABC}$, then which of the following is NOT correct about $\mathrm{△}\mathrm{ABC}=$

$\mathrm{A}(\mathrm{\alpha },-2):\mathrm{B}(\mathrm{\alpha },6):\mathrm{C}\left(\frac{\mathrm{\alpha }}{4},-2\right)$
Since AC is perpendicular to AB.
So, $\mathrm{△}\mathrm{ABC}$ is right angled at A.
Circumcentre = mid point of $\mathrm{BC}.=\left(\frac{5\mathrm{\alpha }}{8},2\right)$
$\therefore \frac{5\mathrm{\alpha }}{8}=5\mathrm{\&}\frac{\mathrm{\alpha }}{4}=2$

Area $=\frac{1}{2}\left(6\right)\left(8\right)=24$
Perimeter = 24
Circumradius = 5
Inradius $=\frac{\mathrm{\Delta }}{\mathrm{s}}=\frac{24}{12}=2$