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Q.

Let a¯=2i¯+j¯-2k¯, b¯=i¯+j¯. If c¯ is a vector such that a¯.c¯=c¯, c¯-a¯=22 and the  angle between a¯×b¯ and c¯ is 300, then a¯×b¯×c¯=

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a

2

b

3/2

c

2/3

d

3

answer is B.

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Detailed Solution

a×b=ijk21-2110=i(0+2)-j(0+2)+k(1)                                =2i-2j+k |a×b|=3 |c-a|=22  |c-a|2=8  |c|2+9-2|c|=8  (|c|-1)2=0  |c|=1 |(a×b)×c|=|a×b| |c|  sin300 =3×1×12=32

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