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Q.

Let a=4i+5j-k,b=i-4j+5k,c=3i+j-k and let α be a vector perpendicular to both a and b such that α.c=63. Then α =

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a

21i-21j-21k

b

7i-7j-7k

c

3i-3j-3k

d

21i-7j-7k

answer is C.

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Detailed Solution

a×b=ijk44-11-45=i(21)-j(21)+k(-21) α  a×b  α=λ(a×b)                       α=21λ(i-j-k)  α·c  =63    21λ(3-1+1)=63  λ=1 α=21i-21j-21k

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