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Q.

Let a=a1i+a2j+a3k, b=b1i+b2j+b3k, c=c1i+c2j+c3k be three non-zero vectors such that c is a unit vector perpendecular to both a and b .

If the angle between a and b is π/ 6 then a1a2a3b1b2b3c1c2c32=

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a

1

b

0

c

34a2b2

d

14a2b2

answer is C.

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Detailed Solution

 =a1a2a3b1b2b3c1c2c32 =[a b c]2 ==(a×b·c)2  =|a×b|2 |c|2 =|a|2 |b|2 sin230×1 =14 |a|2 |b|2

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Let a=a1i+a2j+a3k, b=b1i+b2j+b3k, c=c1i+c2j+c3k be three non-zero vectors such that c is a unit vector perpendecular to both a and b .If the angle between a and b is π/ 6 then a1a2a3b1b2b3c1c2c32=