Let A={a:a∈N, a2−7a+12=0}; B={2,3,4,5,6}, then B−A=

A={a:a∈N, a2−7a+12=0}={3,4}B={2,3,4,5,6}B−A={2,3,4,5,6}−{3,4}={2,5,6}

Let A={a:a∈N, a2−7a+12=0}; B={2,3,4,5,6}, then B−A=

A={a:a∈N, a2−7a+12=0}={3,4}B={2,3,4,5,6}B−A={2,3,4,5,6}−{3,4}={2,5,6}

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Let $A = {a : a \in N, a^{2} - 7 a + 12 = 0}; B = {2, 3, 4, 5, 6}$ , then $B - A =$

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${2, 5, 6, 3}$

$\{2, 3, 4\}$

$\{2, 5, 6\}$

$\{3, 4\}$

answer is C.

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Detailed Solution

$A = {a : a \in N, a^{2} - 7 a + 12 = 0} = {3, 4}$

$B = {2, 3, 4, 5, 6}$

$B - A = {2, 3, 4, 5, 6} - {3, 4} = {2, 5, 6}$

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Let A={a:a∈N, a2−7a+12=0}; B={2,3,4,5,6}, then B−A=

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Let $A = {a : a \in N, a^{2} - 7 a + 12 = 0}; B = {2, 3, 4, 5, 6}$ , then $B - A =$