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Q.

Let ab and c be three non-coplanar  vectors, and let pq and r be the vectors defined by the  relations

p=b×c[abc], q=c×a[abc] and r=a×b[abc] Then the value of the expression (a+b)p+(b+c)q+c+a . r is equal to 

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a

0

b

1

c

2

d

3

answer is D.

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Detailed Solution

ap=a(b×c)[abc]=[abc][abc]=1=bq=crbp=b(b×c)[abc]=0[abc]=0=cq=ar

Therefore, the given expression is equal to 1 + 0 + 1 + 0 + 1 + 0 = 3.

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