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Q.

Let A,B and C be vectors of length 3, 4, 5 respectively. Let A(B+C),B(C+A),C(A+B). Then  the length of  (A+B+C). is

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a

22

b

32

c

42

d

52

answer is D.

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Detailed Solution

A·(B+C)=0,B·(C+A)=0,C·(A+B)=0

Adding A·B+B·C+C·A=0

Now, |A+B+C|2=(A+B+C)·(A+B+C)

=32+42+52+2|A·B+B·C+C·A|=50

|A+B+C|=52.

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