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Q.

Let a, b, c be three vectors mutually perpendicular to each other and have same magnitude. If a vector r satisfies a×r-b×a+b×r-c×b+c×r-a×c=0 then r is equal to

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a

12a+b+2c

b

12a+b+c

c

13a+b+c

d

132a+b-c

answer is C.

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Detailed Solution

Let  a=i   b=j   c=k

i×((r-j)×i)+j×((r-k)×j)+k×((r-i)×k)=0 r-j-(i·r) i+r-k-(j·r) j+r-i-(k·r) k=0 3r-(i+j+k)-r=0   2r=i+j+k=a+b+c r=a+b+c2

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