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Q.

Let a, β be roots of ax2+bx+c=0, where 

ac0. Roots of ax2+bx+c=0 are

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a

1/α,1/β

b

1/α,1/β

c

1/α,1/β

d

1/α,1/β

answer is B.

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Detailed Solution

α+β=b/a,αβ=c/a

Now,               bc=b/ac/a=α+βαβ                         =1α+1βAnd                 ac=1αβ=1α1β

 Thus, roots of cx2bx+a=0 are 1/α,1/β

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