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Q.

Let a +mb +nc =0 . a ×b +b×c+c×a=0 for 

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a

m+n=1

b

m+2n=1

c

m-2n=1

d

m+n=-1

answer is A.

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Detailed Solution

a+mb+nc=0a×(a+mb+nc)=0    m(a×b)=n  (c×a)b×(a+mb+nc)=0    n(b×c)=a×b

given a×b+b×c+c×a=0

n(b×c)+b×c+mn(n(b×c))=0n+1+m=0

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