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Q.

let an+1bn+1=3+113313+1anbn,n=1,2,3 and a1 = b1 = 1 then a2010 =

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a

23013

b

23014

c

22013

d

23015

answer is A.

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Detailed Solution

an+1bn+1=22cosπ12sinπ12sinπ12cosπ12anbna2010b2010=(22)2009cosπ12sinπ12sinπ12cosπ12200911a2010b2010=(22)2009cos2009π12sin2009π12sin2009π12cos2009π1211a2010=(22)2009cos2009π12sin2009π12=(22)200912=23013

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