Q.

Let ⨍  and g be increasing and decreasing functions respectively from [0, ) to [0,) Let h(x)= (g(x). If h(0)=0, then h(x)-h(1) is

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a

always positive

b

strictly increasing

c

always negative

d

always zero

answer is A.

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Detailed Solution

given

⨍ 1(x)<0,  g1(x)<0

for x0

⨍ x, g(x)≥0 h(x)=⨍ (g(x))≥0  - ① h1(x)=⨍ 1(g(x)).g1(x)<0 x0 h(x)0   - 

from eq  & eq 

h(x)=0 h(1)=0 h(x)-h(1)=0

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