Let α and β be the roots of x2−6x−2=0 with α>β. if an=αn−βn for n≥1 then the value of a10−2a82a9 is

α2−2=6αβ2−2=6βa10−2a82a9=6α9−β92α9−β9=3

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

Let $α$ and $β$ be the roots of $x^{2} - 6 x - 2 = 0$ with $α > β . if a_{n} = α^{n} - β^{n} for n \geq 1$ then the value of $\frac{a_{10} - 2 a_{8}}{2 a_{9}}$ is

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 3.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

$α^{2} - 2 = 6 α$

$β^{2} - 2 = 6 β$

$\frac{a_{10} - 2 a_{8}}{2 a_{9}} = \frac{6 (α^{9} - β^{9})}{2 (α^{9} - β^{9})} = 3$

Watch 3-min video & get full concept clarity