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Q.

Let D and E be the midpoints of the sides AC and BC of a triangle ABC respectively. If O is an interior point of the triangle ABC such that OA+2OB+3OC=0, then the area (in sq.units) of the triangle ODE is 
 

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a

6

b

5

c

3/4

d

0

answer is D.

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Detailed Solution

OA=a     OB=b     OC=c OD=a+c2      OE=b+c2 a+2b+3c=0    2(a×b)=3(c×a) b×a+0+3(b×c)=0    3(b×c)=a×b   a×b=3(b×c)=32(c×a)

area   ODE=12OD×OE                         =12a+c2×b×c2                         =18a×b+a×c+c×b                         =18a×b-23(a×b)-13(a×b)=0

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