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Q.

Let e⨍ x=logx. If g(x) is the inverse function of ⨍ x then g1(x)

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a

ex

b

ex-x

c

ex+log x

d

ex-ex

answer is A.

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Detailed Solution

ef(x)=g(x)  f(x)=log(g(x)) g(x)=f-1(x) f(g(x))=x f1(g(x)) g1(x)=1

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