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Q.

Let f: and g:be respectively given by f(x)=|x|+1and g(x)=x2+1.Define h: by h(x)=max.    {f(x),g(x)}    if x0min.    {f(x),g(x)}    if x>0.The number of points at which h(x) is not differentiable is

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a

1

b

2

c

3

d

4

answer is C.

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Detailed Solution

h(x)=x2+1,x<11x,1x0x2+1,0<x11+x,x>0
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h(x) is not differentiable at x=1,0,1

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