Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Let f :  be a function defined as f(x)=asinπ[x]2+[2x], a, where [t] is the greatest integer less than or equal to t. If limx1f(x) exists, then the value of 04f(x)dx is equal to :

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

2

b

1

c

-2

d

-1

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

detailed_solution_thumbnail

limx1+asinπ[x]2+[2x]=a+2

limx1asinπ[x]2+[2x]=0+3=3

limx1f(x) exist when  -a+2=3 a=1

Now, 

04f(x)dx=01f(x)dx+12f(x)dx+23f(x)dx+34f(x)dx=01(0+1)dx+12(1+0)dx+23(01)dx+34(12)dx=1111=2

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon