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Q.

Let f be a twice differentiable function defined on R such that  f0=1,f'0=2and  f1x0for all xR . If fxf'xf'xf"x=0 for all xR, then the value of  f1 lies in the interval

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a

0,3

b

9,12

c

3,6

d

6,9

answer is A.

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Detailed Solution

fxf"x=f1x2    f1x2fxf11xf1x2=0      ddxfxf1x=0  fxf1x=k       k=12

fx=±ke2x  f0=1f1=e2=7.38

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