Let F¯ be the force acting on a particle having position vector r→ & T→ be the torque of this force about the origin. Then

T→=r→×F→r→·T→=0 and F→·T→=0

T→=r→×F→r→·T→=0 and F→·T→=0

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Let $\bar{F}$ be the force acting on a particle having position vector $\vec{r} & \vec{T}$ be the torque of this force about the origin. Then

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$\vec{r} . \vec{T} = 0 and \vec{F} . \vec{T} \neq 0$

$\vec{r} . \vec{T} = 0 and \vec{F} . \vec{T} = 0$

$\vec{r} . \vec{T} \neq 0 and \vec{F} . \vec{T} \neq 0$

$\vec{r} . \vec{T} \neq 0 and \vec{F} . \vec{T} = 0$

answer is A.

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$\vec{T} = \vec{r} \times \vec{F}$

$\vec{r} \cdot \vec{T} = 0 and \vec{F} \cdot \vec{T} = 0$

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