Q.

 Let f:RR such that f''(x)-2f'(x)+f(x)=2ex and f'(x)>0xR then which of the following can be correct

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a

fx=fx  xR

b

fx=fx  xR

c

f3=2

d

f3=242

answer is B, D.

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Detailed Solution

ddxe-xf'(x)-f(x)=2

e-xf'(x)-f(x)=2x+c1

f(x)=x2+c1n+c2ex,f'(x)=exx2+c1+2x+c1+c2

 Gives f'(x)>0x2c1+2x+c1+c2>0Δ<0

C1+22-4C1-C2<0

C12-4C2+4<0

C12-4C2<-4

C12-4C2<0

f(x)>0xR

|f(x)|=f(x)xR  f(x)>ex

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