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Q.

Let f(x)  be a function defined as follows: f(x)=sin(x23x),x0 ; and at 6x+5x2,x>0  then at x=0 , f(x)

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a

has a local maximum

b

is discontinuous

c

is continuous

d

has a local minimum

answer is B.

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Detailed Solution

f(0)=sin0=0f(0+)0+

f(0)=limx0sin(x23x)=limh0sin(h2+3h)0+

Thus, f(0+)>f(0) and  f(0)>f(0)

Hence, x=0  is a point of minima.

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